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Assignment 1

Oct 14, 20238 min read

Q # 1

Publisher (PublisherID, PublisherName, Address) Author (AuthorID, AuthorName, Gender, BirthDate, Country) Book (ISBN, AuthorID, PublisherID, PublishDate, BookTitle)

Table Creation

CREATE TABLE Publisher(
	PublisherID int,
	PublisherName varchar(20),
	Address varchar(max),
	CONSTRAINT PK_Publisher PRIMARY KEY(PublisherID),
);
 
CREATE TABLE Author(
	AuthorID int,
	AuthorName varchar(20),
	Gender varchar(10),
	BirthDate Date,
	Country varchar(20), 
	CONSTRAINT PK_Author PRIMARY KEY(AuthorID),
);
 
CREATE TABLE Book(
	ISBN numeric(13),
	AuthorID int,
	PublisherID int,
	PublishDate Date,
	BookTitle varchar(max),
	CONSTRAINT PK_Book PRIMARY KEY(ISBN),
	CONSTRAINT FK_BookAuthor FOREIGN KEY(AuthorID)
	REFERENCES Author(AuthorID),
	CONSTRAINT FK_BookPublisher FOREIGN KEY(PublisherID)
	REFERENCES Publisher(PublisherID), 
);

Table Insertion

INSERT INTO Publisher
VALUES
	(01, 'Classy Books', '80 Strand, London WC2R 0RL, United Kingdom'),
	(02, 'Rocky Books', '456 Elm Ave, Narnia'),
	(03, 'Awesome Books', 'Some Middle Earth'),
	(04, 'Standy Books', 'Pine Street'),
	(05, 'Catchy Books', 'Ketchup Street, Burger Land, Shami');
 
INSERT INTO Author
VALUES
	(01, 'J.K. Rowling', 'Female', '1965-07-31', 'UK'),
	(02, 'Gary Keller', 'Male', '1957-03-23', 'US'),
	(03, 'Noob Writer', 'Male', '2003-08-12', 'PAK'),
	(04, 'Cool Writer', 'Male', '2001-03-24', 'COOL'),
	(05, 'Invalid Writer', 'Male', '1998-03-23', 'NZ');
 
INSERT INTO Book
Values
	(9780747532743, 01, 01, '1997-06-26', 'Harry Potter'),
	(9780316084127, 05, 01, '2007-03-27', 'City of Noobs'),
	(9780439023528, 03, 02, '2008-09-14', 'City of Freaks'),
	(9780525478812, 04, 04, '2012-01-10', 'The Fault in Our Brains'),
	(9781416949176, 02, 02, '2007-08-02', 'The Light We Seek');

Q # 2

Constraints

  • Account type will either be ‘Current’ or ‘Savings’.
  • Customer will have one account only, thus CustomerID is unique.

Q # 3

Relation: R

ABCD
a4b1c2d1
a2b2c1d1
a2b2c4d2
a1b4c3d1

Super Keys

  • {A, B, C, D}
  • {A, C, D}
  • {A, B, D}
  • {B, C, D}
  • {A, B, C}
  • {A, D}
  • {B, D}
  • {A, C}
  • {B, C}
  • {C, D}
  • {C}

Minimal Super Keys / Candidate Keys

Criteria

Super Key whose proper subsets do not belong to another super key.

  • {C}
  • {B, D}
  • {A, D}

Q # 4

1. INSERT Operation

(a)

INSERT INTO Product VALUES (null, 'Chicken Nuggets', 120, 100);

Fail

Entity Integrity Violation Reason : The Primary Key ProductID cannot be specified as null. A Primary Key has to be non null and unique.

(b)

INSERT INTO Production VALUES (1,'1-2001', 300, '01-Feb-2021', '01-Feb-2022');

Success

Changes :

  • This new record will be inserted into the relation.

(c)

INSERT INTO Production VALUES (1, null, 300, '01-Feb-2021', '01-Feb-2022');

Fail

Entity Integrity Violation Reason : A Primary key by its property cannot be null even if it is composite.

(d)

INSERT INTO Customer VALUES (1,'Packages', 'DHA', '042-31234567');

Fail

Entity Integrity Violation Reason : The Primary key has to be unique but the given value is already present.

(e)

INSERT INTO Order VALUES (5, 10, 1, '09-Feb-2021');

Failure

Referential Integrity Violation Reason : The provided CustomerID does not exist in the parent table of this foreign key field.

2. DELETE Operation with CASCADE

(a)

DELETE FROM Product WHERE ProductID=2;

Success

Changes :

  • Second record will be deleted from the Product relation.
  • Last record in Production relation will also be deleted because of CASCADE option.

(b)

DELETE FROM Customer WHERE CustomerID=1;

Success

Changes :

  • First record will be deleted from the Customer relation.
  • First record in Order relation will also be deleted because of CASCADE option.

(c)

DELETE FROM Production WHERE BatchID='1-1002';

Success

Changes :

  • Second and third record will be deleted from the Production relation.

(d)

DELETE FROM Order WHERE CustomerID=1 OR ProductID=1;

Success

Changes :

  • All the records in the table will be deleted as they satisfy the requirements.

(e)

DELETE FROM Order WHERE OrderNo=4;

Fail

No Changes will be made to the relation as no record will satisfy the criteria.

3. DELETE Operation with SET NULL

(a)

DELETE FROM Product WHERE ProductID=2;

Fail

Referential Integrity Violation Reason : The ProductID attribute is a foreign key and a composite primary key in Production table. As by entity integrity constraint, a primary key cannot be null thus using SET NULL option we will have an error and the operation won’t be executed.

(b)

DELETE FROM Customer WHERE CustomerID=1;

Success

Changes :

  • The first record of Customer relation will be deleted
  • The CustomerID in Order relation with value 1 will be set null.

(c)

DELETE FROM Production WHERE BatchID='1-1002';

Success

Changes :

  • The second and third record will be deleted from the relation.

(d)

DELETE FROM Order WHERE CustomerID=1 OR ProductID=1;

Success

Changes :

  • All the records from the Order relation will be discarded.

(e)

DELETE FROM Order WHERE OrderNo=4;

Failure

No Changes because the identifier is not present in the relation.

4. Delete Operation - with NO ACTION

(a)

DELETE FROM Product WHERE ProductID=2;

Failure

Referential Integrity Violation Reason : As ProductID is being used as Foreign Key in Production relation, we will not be allowed to delete the entry in the Parent table until there are no references to that record in any of the child tables.

(b)

DELETE FROM Customer WHERE CustomerID=1;

Failure

Referential Integrity Violation Reason : CustomerID is being used as a Foreign Key in Order relation, thus we will not be allowed to delete that.

(c)

DELETE FROM Production WHERE BatchID='1-1002';

Success

Changes :

  • The second and third record will be deleted from the Production relation.

(d)

DELETE FROM Order WHERE CustomerID=1 OR ProductID=1;

Success

Changes :

  • All the entries from the Order relation will be deleted.

(e)

DELETE FROM Order WHERE OrderNo=4;

Success

No Changes will be made because the record is not present in the relation.

5. UPDATE Operation - with CASCADE

(a)

UPDATE Order SET CustomerID=10 WHERE CustomerId=2;

Failure

Referential Integrity Violation CustomerID is being used as Foreign Key referencing the Customer relation. We will not be allowed to insert or update values that are not present in the referencing attribute.

(b)

UPDATE Product SET ProductID=21 WHERE ProductID=3;

Success

Changes :

  • The specified ProductID in Product relation will be updated.
  • The foreign keys referring to this ProductID such as in Production and Order table will be updated with this new value if they happen refer it.

(c)

UPDATE Order SET OrderDate= null WHERE ProductID=1;

Success

Change :

  • The OrderDate in second and third records will be updated to null.

(d)

UPDATE Production SET CustomerID=1 WHERE BatchID='1-1002';

Failure

SQL Error Reason : The Production relation does not have an attribute CustomerID.

(e)

UPDATE Production SET BatchNo= null WHERE UnitsProduced=6000;

Failure

Entity Integrity Violation Reason : BatchNo is part of a composite primary key in the Production relation. Therefore, It’s value cannot be specified as null.

6. UPDATE Operation - with SET NULL

(a)

UPDATE Order SET CustomerID=10 WHERE CustomerId=2;

Failure

Referential Integrity Violation The CustomerID in Customer table does not have value 10 in any of the record, so the query will not be executed.

(b)

UPDATE Product SET ProductID=21 WHERE ProductID=3;

Failure

Entity Integrity Violation The ProductID as being used as Foreign Key in Production table, when updated will cause the Production table reference to be set as null but this will not be allowed as it is a part of a composite primary key.

(c)

UPDATE Order SET OrderDate= null WHERE ProductID=1;

Success

Changes : The second and third record of Order table will be set OrderDate as null.

(d)

UPDATE Production SET CustomerID=1 WHERE BatchID='1-1002';

Failure

The given attribute CustomerID is not present in the Production relation.

(e)

UPDATE Production SET BatchNo= null WHERE UnitsProduced=6000;

Failure

Entity Integrity Violation As BatchNo is part of a composite primary key in the Production table, it cannot be updated to null.

7. UPDATE Operation - with NO ACTION

(a)

UPDATE Order SET CustomerID=10 WHERE CustomerId=2;

Failure

Referential Integrity Violation The value 10 is not present in the referencing column of Foreign Key attribute.

(b)

UPDATE Product SET ProductID=21 WHERE ProductID=3;

Failure

The value will not allowed to be updated because of NO ACTION option since this value is being referred by another relation.

(c)

UPDATE Order SET OrderDate= null WHERE ProductID=1;

Success

Changes :

  • The second and third rows will have OrderDate set to null.

(d)

UPDATE Production SET CustomerID=1 WHERE BatchID=’1-1002’;

Failure

The provided attribute CustomerID is not present in the Production table.

(e)

UPDATE Production SET BatchNo= null WHERE UnitsProduced=6000;

Failure

Entity Integrity Violation BatchNo is part of a composite primary key, thus it cannot be put as null.

Q # 5

SQL Date Formats

Object NameFormat
DATEYYYY-MM-DD
YEARYYYY / YY
DATETIMEYYYY-MM-DD HH:MI:SS
TIMESTAMPYYYY-MM-DD HH:MI:SS

For SQL Server

In Addition to above, we also have these:

Object NameFormat
timeHH:MM:SS[.nnnnnn]
SMALLDATETIMEYYYY-MM-DD HH:MI:SS

Q # 6

Composite Primary Key

A Composite Primary Key is created by combining two or more attributes in such a way that when taken together, these attributes uniquely identify each record of the relation. They serve as a primary key and may or may not be unique when taken individually.

Example

Consider the following relation :

NameEye ColorAgeCholesterol
AhmadBrown19144
SairaBlue19184
AmjadBlack20144

The Age and Cholesterol attributes serve as a composite primary key.

Composite Foreign Key

A Composite Foreign Key can be created in a situation when we have a composite primary key in the parent table. In this case, we would need to address both of the primary key attributes as foreign key in the child table.

Example

Consider the following relations :

Relation 1

Account TypeAccount NumAccount Description
Savings324325435435A Saving Account
Salary243242342342A Salary Account

Relation 2

Customer NameAccount TypeAccount Num
AhmadSalary243242342342

Account Type and Account Num serve as composite primary key in Relation 1 and thus composite foreign key in Relation 2.

Graph View

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